goe - 8 months ago 49

Java Question

I run this in Java 7 and I get:

`double remainder1 = 1 % 1000;`

double remainder2 = 0.01 % 1000;

double remainder3 = -1 % 1000;

System.out.println("START: "+remainder1+" | "+remainder2+" | "+remainder3);

>>>START: 1.0 | 0.01 | -1.0

But when I run the same operations in Perl 5.8.8 I get different results for two out of three:

`my $remainder1 = 1 % 1000;`

my $remainder2 = 0.01 % 1000;

my $remainder3 = -1 % 1000;

print "START: $remainder1 | $remainder2 | $remainder3";

>>>START: 1 | 0 | 999

Why is there such a difference in the last two calculations?

How can I get perl to match java results?

Answer

Use the `POSIX::fmod`

function.

This is identical to the C function fmod().

```
$r = fmod($x, $y);
```

It returns the remainder

`$r = $x - $n*$y`

, where`$n = trunc($x/$y)`

. The`$r`

has the same sign as`$x`

and magnitude (absolute value) less than the magnitude of`$y`

.

```
use POSIX 'fmod';
$m1 = fmod(1, 1000); # 1
$m2 = fmod(0.01, 1000); # 0.01
$m3 = fmod(-1, 1000); # -1
```

Source (Stackoverflow)