Christoph_J Christoph_J - 1 year ago 61
R Question

Is my way of duplicating rows in data.table efficient?

I have monthly data in one

and annual data in another
and now I want to match the annual data to the respective observation in the monthly data.

My approach is as follows: Duplicating the annual data for every month and then join the monthly and annual data. And now I have a question regarding the duplication of rows. I know how to do it, but I'm not sure if it is the best way to do it, so some opinions would be great.

Here is an exemplatory
data.table DT
for my annual data and how I currently duplicate:

DT <- data.table(ID = paste(rep(c("a", "b"), each=3), c(1:3, 1:3), sep="_"),
values = 10:15,
startMonth = seq(from=1, by=2, length=6),
endMonth = seq(from=3, by=3, length=6))
ID values startMonth endMonth
[1,] a_1 10 1 3
[2,] a_2 11 3 6
[3,] a_3 12 5 9
[4,] b_1 13 7 12
[5,] b_2 14 9 15
[6,] b_3 15 11 18
#1. Alternative
DT1 <- DT[, list(MONTH=startMonth:endMonth), by="ID"]
setkey(DT, ID)
setkey(DT1, ID)
ID MONTH values startMonth endMonth
a_1 1 10 1 3
a_1 2 10 1 3
a_1 3 10 1 3
a_2 3 11 3 6

The last join is exactly what I want. However,
DT[, list(MONTH=startMonth:endMonth), by="ID"]
already does everything I want except adding the other columns to
, so I was wondering if I could get rid of the last three rows in my code, i.e. the
operations. It turns out, you can, just do the following:

#2. Alternative: More intuitiv and just one line of code
DT[, list(MONTH=startMonth:endMonth, values, startMonth, endMonth), by="ID"]
ID MONTH values startMonth endMonth
a_1 1 10 1 3
a_1 2 10 1 3
a_1 3 10 1 3
a_2 3 11 3 6

This, however, only works because I hardcoded the column names into the
expression. In my real data, I do not know the names of all columns in advance, so I was wondering if I could just tell
to return the column
that I compute as shown above and all the other columns of
seemed to be able to do the trick, but:

DT[, list(MONTH=startMonth:endMonth, .SD), by="ID"]
Error in `[.data.table`(DT, , list(YEAR = startMonth:endMonth, .SD), by = "ID") :
maxn (4) is not exact multiple of this j column's length (3)

So to summarize, I know how it's been done, but I was just wondering if this is the best way to do it because I'm still struggling a little bit with the syntax of
and often read in posts and on the wiki that there are good and bads ways of doing things. Also, I don't quite get why I get an error when using
. I thought it is just any easy way to tell
that you want all columns. What do I miss?

Answer Source

Great question. What you tried was very reasonable. Assuming you're using v1.7.1 it's now easier to make list columns. In this case it's trying to make one list column out of .SD (3 items) alongside the MONTH column of the 2nd group (4 items). I'll raise it as a bug [EDIT: now fixed in v1.7.5], thanks.

In the meantime, try :

DT[, cbind(MONTH=startMonth:endMonth, .SD), by="ID"]
 ID MONTH values startMonth endMonth
a_1     1     10          1        3
a_1     2     10          1        3
a_1     3     10          1        3
a_2     3     11          3        6

Also, just to check you've seen roll=TRUE? Typically you'd have just one startMonth column (irregular with gaps) and then just roll join to it. Your example data has overlapping month ranges though, so that complicates it.

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