dvdktn - 1 year ago 178

Python Question

`def classify(numb):`

i=1

j=1

sum=0

for i in range(numb):

for j in range(numb):

if (i*j==numb):

sum=sum+i

sum=sum+j

if sum>numb:

print("The value",numb,"is an abundant number.")

elif sum<numb:

print("The value",numb,"is a deficient number.")

else:

print("The value",numb,"is a perfect number.")

break

return "perfect"

The code takes a number(numb) and classifies it as an abundant, deficient or perfect number. My output is screwy and only works for certain numbers. I assume it's indentation or the break that I am using incorrectly. Help would be greatly appreciated.

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Answer Source

I would highly recommend u to create a one function which creates the proper divisor of given N, and after that, the job would be easy.

```
def get_divs(n):
return [i for i in range(1, n) if n % i == 0]
def classify(num):
divs_sum = sum(get_divs(num))
if divs_sum > num:
print('{} is abundant number'.format(num))
elif divs_sum < num:
print('{} is deficient number'.format(num))
elif divs_sum == num:
print('{} is perfect number'.format(num))
```