yobro97 - 1 year ago 87

C Question

Given an integer

`k`

`103993/33102`

`k`

`int k ;`

scanf("%d",&k);

printf("3");

if(k>0)

printf(".");

long long int num=30;

long long int numer = 1039930;

long long int denom = 33102;

while(k--)

{

long long int bro = numer/denom;

printf("%lld",bro-num);

num=bro;

num*=10;

numer*=10;

}

But if

`k`

`20`

http://ideone.com/dndib2

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

Your problem is overflow.

with `num *= 10;`

and `numer *= 10;`

in your loop, looping 20 times means 10 ^20 (10 to the power of 20) and with `long long int`

being 64 bits it can hold a maximum of 18,446,744,073,709,551,615 (2^64-1) which is less than 10^20.