Ishrat - 26 days ago 10

C++ Question

Here is my 2D vector of integers.

`vector<vector<int>> nodes (r*c, vector<int> (5));`

using a for loop I am trying to push_back values in this vector. r and c are passed integers to this function.

`for(i = 0; i < r*c; i++)`

{

nodes[i].push_back({i/c, i%c, -1, -1, 0});

}

Answer

`nodes[i]`

is a vector of *integers*. You're trying to append a *vector* to a vector of integers.

Either do:

```
nodes.push_back({i/c, i%c, -1, -1, 0});
```

or

```
nodes[i] = {i/c, i%c, -1, -1, 0};
```

The second solution being the best since you already gave the proper dimension to your vector. No need to add `r*c`

more elements...

in your code, either create empty, and populate with `push_back`

:

```
std::vector<std::vector<int>> nodes;
for(i = 0; i < r*c; i++)
{
nodes.push_back({i/c, i%c, -1, -1, 0});
}
```

or create with proper dimension and assign items:

```
std::vector<std::vector<int>> nodes (r*c, std::vector<int> (5));
for(i = 0; i < r*c; i++)
{
nodes[i] = {i/c, i%c, -1, -1, 0};
}
```

Source (Stackoverflow)

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