Perl Dog Perl Dog - 2 years ago 111
Perl Question

How to make Time::Piece respect DST when converting localtime to UTC?

I want to convert a timestamp from localtime to GMT. I have legacy code that does this "manually" with

. It works, but I don't like it and wanted to use
instead. I used this answer to do so (albeit they are converting the other way round, but I was able to replace

This is my code:

#!/usr/bin/env perl

use strict;
use warnings;
use Time::Local;
use Time::Piece;
use POSIX qw(strftime);

sub local_to_utc_timelocal
my $local_ts = shift;
my ( $year, $mon, $mday, $hour, $min, $sec )
= ( $local_ts =~ /(\d\d)-(\d\d)-(\d\d) (\d\d):(\d\d):(\d\d)/ );
my $local_secs = Time::Local::timelocal( $sec, $min, $hour, $mday, $mon - 1, $year );
return POSIX::strftime( '%y-%m-%d %H:%M:%S', gmtime($local_secs) );

sub local_to_utc_timepiece
my $local_ts = shift;
my $local_tp = Time::Piece->strptime( $local_ts, '%y-%m-%d %H:%M:%S' );
my $utc_tp = $local_tp - localtime->tzoffset(); # ***
return $utc_tp->strftime('%y-%m-%d %H:%M:%S');

my $local;

# DST in effect (April 19 2016):
$local = '16-04-19 14:30:00';
print "DST in effect:\n";
printf("utc(%s) = %s (using timelocal)\n", $local, local_to_utc_timelocal($local));
printf("utc(%s) = %s (using timepiece)\n\n", $local, local_to_utc_timepiece($local));

# DST NOT in effect (Feb 19 2016):
$local = '16-02-19 14:30:00';
print "DST NOT in effect:\n";
printf("utc(%s) = %s (using timelocal)\n", $local, local_to_utc_timelocal($local));
printf("utc(%s) = %s (using timepiece)\n", $local, local_to_utc_timepiece($local));

Unfortunately the Time::Piece code doesn't seem to work properly wrt DST. I'm living in Germany, so currently (spring/summer, DST in effect) we are UTC+2. For "April 19 2016" the above code gives:

DST in effect:
utc(16-04-19 14:30:00) = 16-04-19 12:30:00 (using timelocal)
utc(16-04-19 14:30:00) = 16-04-19 12:30:00 (using timepiece)

which is correct. But for "Feb 19 2016" (when we are UTC+1) the same code gives:

DST NOT in effect:
utc(16-02-19 14:30:00) = 16-02-19 13:30:00 (using timelocal)
utc(16-02-19 14:30:00) = 16-02-19 12:30:00 (using timepiece)

That is: The
gives correct 1 hour offset while
still gives 2 hours offset.

Is this a bug in
or do I use it wrongly?

I know there are plenty of ways to convert localtime to UTC but I'd like to use
because of its simplicity. Plus I cannot use
because that would involve deploying it on a dozen of production machines.

Answer Source

Problem 1

localtime returns now, so localtime->tzoffset() returns the offset for now. Change




Problem 2

Despite its name, $local_tp is not a local time, so $local_tp->tzoffset() is zero. Change

Time::Piece->strptime( $local_ts, '%y-%m-%d %H:%M:%S' )


localtime->strptime( $local_ts, '%y-%m-%d %H:%M:%S' );
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