Lewis Day Lewis Day - 6 months ago 10
PHP Question

How do I define an array value from a integer?

Okay below I have attached my code, I'm trying to use the

$current_statement
and
$next_statement
to define the values in the array. the
$current_statement
is = to 7 and the
$next_statement
is = to 8. What I'm trying to do is define the 7th and 8th value in the array from the using the two values from
$current_statement
and
$next_statement
.

<?
$date = array('16-01-14','16-01-28','16-02-14','16-02-28','16-03-14','16-03-28',
'16-04-14','16-04-28','16-05-14','16-05-28','16-06-14','16-06-28','16-07-14',
'16-07-28','16-08-14','16-08-28','16-09-14','16-09-28','16-10-14','16-10-28',
'16-11-14','16-11-28','16-12-14','16-12-28');


$currentdate = date('y-m-d');


foreach ($date as $i => $d) {
if ($currentdate >= $d && ($i == count($date)-1 || $currentdate < $date[$i+1])) {
$current_statement = $i;
$next_statement = $i+1;
}

}

?>


Example

I'm trying to use the two numeric values from the
$current_statement
and the
$next_statement
to select the value from the array. So for example if the
$current_statement
was = to 7 it would select the 7th value from the array and define it as a separate variable. And if the
$next_statement
was = to 8 it would select the 8th value from the array and define it as a separate variable. So I could easily echo out both variables.

Answer

I am not totally clear on your requirement, so this answer is a bit of a guess, which of course I should not really do. But do you mean something like this

<?php
    $date = array('16-01-14','16-01-28','16-02-14','16-02-28','16-03-14',
                  '16-03-28','16-04-14','16-04-28','16-05-14','16-05-28',
                  '16-06-14','16-06-28','16-07-14', '16-07-28','16-08-14',
                  '16-08-28','16-09-14','16-09-28','16-10-14','16-10-28',
                  '16-11-14','16-11-28','16-12-14','16-12-28');    

    $currentdate = date('y-m-d');

    foreach ($date as $i => $d) {
        if ($currentdate >= $d && ($i == count($date)-1 || $currentdate < $date[$i+1])) {
            echo 'Current statement date = ' . $date[$i];
            echo 'Next statement date = ' . $date[$i+1];
        } 
    }
?>

In which case you do not need the 2 variables you created, you can just use $i and $i+1