d_zero - 5 months ago 8x

Ruby Question

The below code is my newbie take on a bubble sort method.

`#For each element in the list, look at that element and the element`

#directly to it's right. Swap these two elements so they are in

#ascending order.

def bubble_sort (array)

a = 0

b = 1

until (array.each_cons(2).all? { |a, b| (a <=> b) <= 0}) == true do

sort = lambda {array[a] <=> array[b]}

sort_call = sort.call

loop do

case sort_call

when -1 #don't swap

a += 1

b += 1

break

when 0 #don't swap

a += 1

b += 1

break

when 1 #swap

array.insert(a,array.delete_at(b))

a += 1

b += 1

break

else #end of array, return to start

a = 0

b = 1

break

end

end

end

puts array.inspect

end

array = [4, 2, 5, 6, 3, 23, 5546, 234, 234, 6]

bubble_sort(array)

I want to be able to alter this method so that it takes a block of code as an argument and uses this to determine how it sorts.

For example:

`array = ["hello", "my", "name", "is", "daniel"]`

bubble_sort(array) {array[@a].length <=> array[@b].length}

(When I've tried this I've turned

`a`

`b`

I have tried using

`yield`

`undefined method 'length' for nil:NilClass`

`if array[@b+1] == nil`

@a = 0

@b = 1

end

This helps but I still end up with weird problems like infinite loops or not being able to sort more than certain amount of elements.

Long story short, I have been at this for hours. Is there a simple way to do what I want to do? Thanks.

Answer

The way you're calling your lambda is a bit odd. It's actually completely unnecessary. I refactored your code and cleaned up a bit of the redundancy. The following works for me:

```
def sorted?(arr)
arr.each_cons(2).all? { |a, b| (a <=> b) <= 0 }
end
def bubble_sort (arr)
a = 0
b = 1
until sorted?(arr) do
# The yield call here passes `arr[a]` and `arr[b]` to the block.
comparison = if block_given?
yield(arr[a], arr[b])
else
arr[a] <=> arr[b]
end
if [-1, 0, 1].include? comparison
arr.insert(a, arr.delete_at(b)) if comparison == 1
a += 1
b += 1
else
a = 0
b = 1
end
end
arr
end
sample_array = [4, 2, 5, 6, 3, 23, 5546, 234, 234, 6]
# Sanity check:
100.times do
# `a` is the value of `arr[a]` in our function above. Likewise for `b` and `arr[b]`.
print bubble_sort(sample_array.shuffle) { |a, b| a <=> b }, "\n"
end
```

**EDIT**

A cleaner version:

```
# In place swap will be more efficient as it doesn't need to modify the size of the arra
def swap(arr, idx)
raise IndexError.new("Index #{idx} is out of bounds") if idx >= arr.length || idx < 0
temp = arr[idx]
arr[idx] = arr[idx + 1]
arr[idx + 1] = temp
end
def bubble_sort(arr)
loop do
sorted_elements = 0
arr.each_cons(2).each_with_index do |pair, idx|
comparison = if block_given?
yield pair.first, pair.last
else
pair.first <=> pair.last
end
if comparison > 0
swap(arr, idx)
else
sorted_elements += 1
end
end
return arr if sorted_elements >= arr.length - 1
end
end
# A simple test
sample_array = [4, 2, 2, 2, 2, 2, 5, 5, 6, 3, 23, 5546, 234, 234, 6]
sample_str_array = ["a", "ccc", "ccccc"]
100.times do
print bubble_sort(sample_array.shuffle) { |a, b| a <=> b }, "\n"
print bubble_sort(sample_str_array.shuffle) { |a, b| a.length <=> b.length }, "\n"
end
```

Source (Stackoverflow)

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