Sait Sait - 4 years ago 143
Python Question

Set contains for user defined classes using __hash__ function

class T:
def __hash__(self):
return 1234

t1 = T()
t2 = T()

my_set = { t1 }

print t2 in my_set

Isn't this supposed to print
have the same hash value. How can I make the
operator of the
use the given hash function?

Answer Source

You need to define an __eq__ method because only instances that are identical a is b or equal a == b (besides having the same hash) will be recognized as equal by set and dict:

class T:
    def __hash__(self):
        return 1234
    def __eq__(self, other):
        return True

t1 = T()
t2 = T()

my_set = { t1 }

print(t2 in my_set)  # True

The data model on __hash__ (and the same documentation page for Python 2) explains this:


Called by built-in function hash() and for operations on members of hashed collections including set, frozenset, and dict. __hash__() should return an integer. The only required property is that objects which compare equal have the same hash value; it is advised to mix together the hash values of the components of the object that also play a part in comparison of objects by packing them into a tuple and hashing the tuple.

If a class does not define an __eq__() method it should not define a __hash__() operation either; if it defines __eq__() but not __hash__(), its instances will not be usable as items in hashable collections. If a class defines mutable objects and implements an __eq__() method, it should not implement __hash__(), since the implementation of hashable collections requires that a key’s hash value is immutable (if the object’s hash value changes, it will be in the wrong hash bucket).

User-defined classes have __eq__() and __hash__() methods by default; with them, all objects compare unequal (except with themselves) and x.__hash__() returns an appropriate value such that x == y implies both that x is y and hash(x) == hash(y).

(Emphasis mine)

Note: In Python 2 you can also implement a __cmp__ method instead of __eq__.

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