user1050619 user1050619 - 1 year ago 131
Python Question

MultiPartParserError :- Invalid boundary

Im trying to send some data and file using Python requests module to my django rest application but get the below error.

raise MultiPartParserError('Invalid boundary in multipart: %s' % boundary)
MultiPartParserError: Invalid boundary in multipart: None


import requests
'company-detail':{'description':'We are a renowned engineering company'
,'addr1':'1280 wick ter'
files = {'upload_file':open('./','rb')}
import json
headers = {'content-type' : 'application/json'}
headers = {'content-type' : 'multipart/form-data'}

#r ='',data=json.dumps(payload),headers=headers,files=files)
r ='',data=payload,headers=headers,files=files)
print r.status_code
print r.text

Django code:-

class CompanyCreateApiView(CreateAPIView):
parser_classes = (MultiPartParser, FormParser,)
def post(self, request, *args, **kwargs):
print 'request ==',

Answer Source

Okay, I forgot about your headers. According to the spec:

Content-Type   = "Content-Type" ":" media-type

MIME provides for a number of "multipart" types -- encapsulations of one or more entities within a single message-body. All multipart types share a common syntax, ... and MUST include a boundary parameter as part of the media type value.

Here is what a request containing multipart/form-data looks like:

POST /myapp/company/ HTTP/1.1
Host: localhost:8000
Content-Length: 265
Accept-Encoding: gzip, deflate
Accept: */*
User-Agent: python-requests/2.9.0
Connection: keep-alive
Content-Type: multipart/form-data; boundary=63c5979328c44e2c869349443a94200e   

Content-Disposition: form-data; name="hello"

Content-Disposition: form-data; name="mydata"; filename="data.txt"

line 1
line 2
line 3
line 4


See how the sections of data are separated by the boundary:


The idea is to use something for a boundary that is unlikely to appear in the data. Note that the boundary was included in the Content-Type header of the request.

That request was produced by this code:

import requests

myfile = {'mydata': open('data.txt','rb')}

r =, 
        #headers = myheaders
        data = {'hello': 'world'}, 
        files = myfile

It looks like you were paying careful attention to the following note in the django-rest-framework docs:

Note: When developing client applications always remember to make sure you're setting the Content-Type header when sending data in an HTTP request.

If you don't set the content type, most clients will default to using 'application/x-www-form-urlencoded', which may not be what you wanted.

But when you are using requests, if you specify the Content-Type header yourself, then requests assumes that you know what you're doing, and it doesn't overwrite your Content-Type header with the Content-Type header it would have provided.

You didn't provide the boundary in your Content-Type header--as required. How could you? You didn't assemble the body of the request and create a boundary to separate the various pieces of data, so you couldn't possibly know what the boundary is.

When the django-rest-framework note says that you should include a Content-Type header in your request, what that really means is:

You or any programs you use to create the request need to include a Content-Type header.

So @AChampion was exactly right in the comments: let requests provide the Content-Type header, after all the requests docs advertise:

Requests takes all of the work out of Python HTTP/1.1

requests works like this: if you provide a files keyword arg, then requests uses a Content-Type header of multipart/form-data and also specifies a boundary in the header; then requests assembles the body of the request using the boundary. If you provide a data keyword argument then requests uses a Content-Type of application/x-www-form-urlencoded, which just assembles all the keys and values in the dictionary into this format:


No boundary required.

And, if you provide both a files keyword arg and a data keyword arg, then requests uses a Content-Type of multipart/form-data.

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