lightsnail - 9 days ago 4

R Question

`j`

`j <- list(matrix(1:12,3),matrix(50:61,3))`

> j

[[1]]

[,1] [,2] [,3] [,4]

[1,] 1 4 7 10

[2,] 2 5 8 11

[3,] 3 6 9 12

[[2]]

[,1] [,2] [,3] [,4]

[1,] 50 53 56 59

[2,] 51 54 57 60

[3,] 52 55 58 61

`k`

`k <- list(matrix(c(T,T,T,T,T,T,F,T,F,F,F,F),3,byrow = T),`

matrix(c(T,F,T,F,F,T,T,T,F,F,F,F),3,byrow = T))

> k

[[1]]

[,1] [,2] [,3] [,4]

[1,] TRUE TRUE TRUE TRUE

[2,] TRUE TRUE FALSE TRUE

[3,] FALSE FALSE FALSE FALSE

[[2]]

[,1] [,2] [,3] [,4]

[1,] TRUE FALSE TRUE FALSE

[2,] FALSE TRUE TRUE TRUE

[3,] FALSE FALSE FALSE FALSE

`j`

`k`

`j`

`TRUE`

`j`

Let me explain it with examples:

The first row in the first object of

`j`

`1 4 7 10`

`k`

`TRUE TRUE TRUE TRUE`

`j`

`j`

`j`

`j`

`1/22 4/22 7/22 10/22`

`0.04545455 0.18181818 0.31818182 0.45454545`

Another example: the second row in the first object of

`j`

`2 5 8 11`

`k`

`TRUE TRUE FALSE TRUE`

`j`

`j`

`j`

`2/18 5/18 8/18 11/18`

`0.1111111 0.2777778 0.4444444 0.6111111`

So the final expected result is:

`[[1]]`

[,1] [,2] [,3] [,4]

[1,] 0.04545455 0.18181818 0.31818182 0.45454545

[2,] 0.1111111 0.2777778 0.4444444 0.6111111

[3,] Inf Inf Inf Inf

[[2]]

[,1] [,2] [,3] [,4]

[1,] 0.4716981 0.5000000 0.5283019 0.5566038

[2,] 0.2982456 0.3157895 0.3333333 0.3508772

[3,] Inf Inf Inf Inf

I find that the

`Map(function(a,b) a[b], j, k)`

`sum`

Answer

You can use `Map`

and `rowSums`

, Map is used to loop through `j`

and `k`

at the same time, and `rowSums`

can be used to calculate the conditional sum of rows by simply multiplying matrices in `j`

with matrices in `k`

:

```
Map(function(x,y) x/rowSums(x*y), j, k)
# [[1]]
# [,1] [,2] [,3] [,4]
# [1,] 0.04545455 0.1818182 0.3181818 0.4545455
# [2,] 0.11111111 0.2777778 0.4444444 0.6111111
# [3,] Inf Inf Inf Inf
#
# [[2]]
# [,1] [,2] [,3] [,4]
# [1,] 0.4716981 0.5000000 0.5283019 0.5566038
# [2,] 0.2982456 0.3157895 0.3333333 0.3508772
# [3,] Inf Inf Inf Inf
```

Source (Stackoverflow)

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