zazvorniki zazvorniki - 8 months ago 117
CSS Question

Customizable jquery mask

I've been playing with a masking function to allow users to type in numbers and it masks them out based on a certain pattern.

For example they type 123456789, but it appears in the field as XXX-XX-6789

Right now I have it hard coded to one pattern, but I would like to expand this to allow them to choose what ever pattern they wish. This is mainly if a client has a loyalty card or something along those lines. Is there a simple way of doing this without hard coding each pattern I think they may want?

My html

<p class="maskNum">
<input type="text" class="form-control mask" autocomplete="off" maxlengthsocial="9" maxlength="11" />
<input type="text" class="form-control maskval" autocomplete="off" maxlengthsocial="9" maxlength="9" />

my css

.maskNum {
position: relative;

.maskval {
position: absolute;
top: 0;
color: transparent !important;
background: transparent !important;
border: none;
left: 0;
text-indent: -9999px;

my jquery

var pattern = 'xxx-xx-0000'

$('.maskval').on('keyup keydown change', function() {
var res = this.value,
len = res.length,
max = 9,
stars = len > 0 ? len > 1 ? len > 2 ? len > 3 ? len > 4 ? 'XXX-XX-' : 'XXX-X' : 'XXX-' : 'XX' : 'X' : '',
result = stars + res.substring(5),
truckResult = result.substring(0, 11);

and a fiddle that I made to test what I've built so far.


If your patterns are only going to contain numbers and x´s:

var pattern = 'x0x-0x-00x0'
$('.maskval').on('keyup keydown change', function() {
var input = $(this).val();
var output = "";
for(var x=0; x<input.length; x++){
        output = pattern[x]=='x' ? output+'x' :  output+input[x];        
        output += input[x];//or nothing if you want the value to be only as long as the pattern

if(input.length < pattern.length && pattern[input.length]=='-'){