John Dibling John Dibling - 1 year ago 187
C++ Question

Lambda capture as const reference?

Is it possible to capture by const reference in a lambda expression?

I want the assignment marked below to fail, for example:

#include <cstdlib>
#include <vector>
#include <string>
#include <algorithm>
using namespace std;

int main()
string strings[] =
static const size_t num_strings = sizeof(strings)/sizeof(strings[0]);

string best_string = "foo";

for_each( &strings[0], &strings[num_strings], [&best_string](const string& s)
best_string = s; // this should fail
return 0;

Update: As this is an old question, it might be good to update it if there are facilities in C++14 to help with this. Do the extensions in C++14 allow us to capture a non-const object by const reference? (August 2015)

Answer Source

const isn't in the grammar for captures as of n3092:

  & identifier

The text only mention capture-by-copy and capture-by-reference and doesn't mention any sort of const-ness.

Feels like an oversight to me, but I haven't followed the standardization process very closely.

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