gsamaras gsamaras - 1 year ago 65
Python Question

Create an RDD with more elements than its source

I have an RDD called

, which is a pair, that has a string as its 1st half and another pair as its 2nd half:

In [76]: codes.collect()
[(u'3362336966', (6208, 5320)),
(u'7889466042', (4140, 5268))]

and I am trying to get this:

In [76]: codes.collect()
[(u'3362336966', 6208),
(u'3362336966', 5320),
(u'7889466042', 4140),
(u'7889466042', 5268)]

How to do this?

My failed attempt:

In [77]: codes_in = x: (x[0], x[1][0]), (x[0], x[1][1]))
NameError Traceback (most recent call last)
<ipython-input-77-e1c7925bc075> in <module>()
----> 1 codes_in = x: (x[0], x[1][0]), (x[0], x[1][1]))

NameError: name 'x' is not defined

Answer Source

I think what you want is the following:

codes_in = x: [(x[0], p) for p in x[1]]).flatMap(lambda x: x)

If it is python 2, for legibility you could:

codes_in = k, vs: [(k, v) for v in vs]).flatMap(lambda x: x)

By this way you will be able to "extract" each value associated with the key and force that every row is a record of form (k, v).

Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download