Larry Cai Larry Cai - 2 months ago 8
Git Question

How to create file execute mode permissions in Git on Windows?

I use Git in Windows, and want to push the executable shell script into git repo by one commit.

Usually I need to do two steps (

git commit
).

$ vi install.sh
$ git add install.sh
$ git commit -am "add new file for installation" # first commit
[master f2e92da] add support for install.sh
1 files changed, 18 insertions(+), 3 deletions(-)
create mode 100644 install.sh
$ git update-index --chmod=+x install.sh
$ git commit -am "update file permission" # second commit
[master 317ba0c] update file permission
0 files changed
mode change 100644 => 100755 install.sh


How can I combine these two steps into one step ? git configuration ? windows command ?

Reference: see question in Git file permissions on Windows 7 for second commit

Answer

There's no need to do this in two commits, you can add the file and mark it executable in a single commit:

C:\Temp\TestRepo>touch foo.sh

C:\Temp\TestRepo>git add foo.sh

C:\Temp\TestRepo>git ls-files --stage
100644 e69de29bb2d1d6434b8b29ae775ad8c2e48c5391 0       foo.sh

As you note, after adding, the mode is 0644 (ie, not executable). However, we can mark it as executable before committing:

C:\Temp\TestRepo>git update-index --chmod=+x foo.sh

C:\Temp\TestRepo>git ls-files --stage
100755 e69de29bb2d1d6434b8b29ae775ad8c2e48c5391 0       foo.sh

And now the file is mode 0755 (executable).

C:\Temp\TestRepo>git commit -m"Executable!"
[master (root-commit) 1f7a57a] Executable!
 1 file changed, 0 insertions(+), 0 deletions(-)
 create mode 100755 foo.sh

And now we have a single commit with a single executable file.

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