Martin Cote Martin Cote - 5 months ago 32
C++ Question

Why do we even need the "delete[]" operator?

This is a question that's been nagging me for some time. I always thought that C++ should have been designed so that the "delete" operator (without brackets) works even with the "new[]" operator.

In my opinion, writing this:

int* p = new int;

should be equivalent to allocating an array of 1 element:

int* p = new int[1];

If this was true, the "delete" operator could always be deleting arrays, and we wouldn't need the "delete[]" operator.

Is there any reason why the "delete[]" operator was introduced in C++? The only reason I can think of is that allocating arrays has a small memory footprint (you have to store the array size somewhere), so that distinguishing "delete" vs "delete[]" was a small memory optimization.


It's so that the destructors of the individual elements will be called. Yes, for arrays of PODs, there isn't much of a difference, but in C++, you can have arrays of objects with non-trivial destructors.

Now, your question is, why not make new and delete behave like new[] and delete[] and get rid of new[] and delete[]? I would go back Stroustrup's "Design and Evolution" book where he said that if you don't use C++ features, you shouldn't have to pay for them (at run time at least). The way it stands now, a new or delete will behave as efficiently as malloc and free. If delete had the delete[] meaning, there would be some extra overhead at run time (as James Curran pointed out).