Christian - 1 month ago 17
C Question

# C math lib - float miscalculations?

I am aware of floating points in C not being very precise. But I have a sniplet where I do not understand why I am getting such results.
First, if I do the calculate within one line I am getting a wrong "0" as result.
Just if I split the same calculations into several commands I am getting nearly what I would expect.

So first questions:

1. Why is the single line different from the split lines?

2. Is there any way how to calculate in a more precise way? I mean, 320-(10.44*4) should be 278.24 and not 278.23999! I understand rounding issues at number like roots or pi or so. But not in above example.

Ok, here is my code (minimized sniplet):

``````#include <math.h>
#include <stdio.h>

float kurv_steil,
kurv_korr,
t_abl_s,
t_out,
t_abl_s,
b,
t_tank_s;

void main()
{
t_tank_s=32;
kurv_steil=0.85;
kurv_korr=-5;
t_out=1.44;
t_abl_s=24;

printf("Werte: k_steil: %f k_korr: %f t_out: %f t_abl_s: %f\n",kurv_steil,kurv_korr,t_out,t_abl_s);
b= pow(t_abl_s,(t_out/(320-(t_out*4) )))*0.65*kurv_steil*b*(-t_out+20);

printf("[temp] Ganze Rechnung tank_s: %f\n",b);
b=320-(t_out*4);

printf("[temp] 320-(t_out*4) b: %f\n",b);
b=t_out/b;

printf("[temp] t_out/b b: %f\n",b);
b=pow(t_abl_s,b);

printf("[temp] t_abl_s^b b: %f\n",b);
b=0.65*kurv_steil*b;

printf("[temp] 0.65*kurv_steil*b b: %f\n",b);
b=b*(-t_out+20);

printf("[temp] b*(-t_out+20) b: %f\n",b);
b=2*b+t_abl_s+kurv_korr;

printf("[temp] 2*b*(-t_abl_s) b: %f\n",b);
}
``````

Output is:

``````Werte: k_steil: 0.850000 k_korr: -5.000000 t_out: 1.440000 t_abl_s: 24.000000
[temp] Ganze Rechnung tank_s: 0.000000
[temp] 320-(t_out*4) b: 314.239990
[temp] t_out/b b: 0.004582
[temp] t_abl_s^b b: 1.014670
[temp] 0.65*kurv_steil*b b: 0.560605
[temp] b*(-t_out+20) b: 10.404831
[temp] 2*b*(-t_abl_s) b: 39.809662
``````

I would expect to have the first output have the same value of "39.809662", but it always has "0". Why?

as told above the problem is in formula you use. You have `b=... *b*...`. The `b` has unknown value by this moment (most likely compiler set it to 0) so you have `b=...*0*...` which makes end result has 0 value.

Also you should add `2* ... + t_abl_s+kurv_korr` to your formula

So the formula will looks like

``````b= 2 *
pow(t_abl_s,(t_out/(320-(t_out*4) ))) *
0.65 * kurv_steil *
(-t_out+20) +
t_abl_s + kurv_korr;
``````
Source (Stackoverflow)