Erdogan CEVHER - 1 year ago 98
R Question

# How to find F value that corresponds to a specific p value, e.g. p=0.05 in R?

I want to find the F value (of a one(right)-tailed distribution) that will correspond to p=0.05 given pre-specified two degrees of freedom (1 and 29 below). I do this by trial and error:

``````#..F values..............p values...
1-pf(4.75, 1, 29)    # 0.03756451
1-pf(4.15, 1, 29)    # 0.05085273
1-pf(4.18295, 1, 29) # 0.05000037
1-pf(4.18297, 1, 29) # 0.04999985
1-pf(4.18296, 1, 29) # 0.05000011
``````

So, I want to obtain F=4.18296 without trial and error. Any idea?

There are two possibilities to achieve such result, we need to use the quantile function:

`qf(1 - 0.05, 1, 29)` or `qf(0.05, 1, 29, lower.tail = FALSE)`

``````qf(1 - 0.05, 1, 29)
# [1] 4.182964

qf(0.05, 1, 29, lower.tail = FALSE)
# [1] 4.182964

1 - pf(4.182964, 1, 29)
# [1] 0.05000001
``````

The first option takes into account that the default option of `lower.tail` is equal to `TRUE` so we have to use 1 - 0.05

For the second option, we specify that we want P[X > x] using `lower.tail = FALSE`

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