grad = (1/m * (h-y)' * X) + lambda * [0;theta(2:end)]'/m;
cost = 1/(m) * sum(-y .* log(h) - (1-y) .* log(1-h)) + lambda/m/2*sum(theta(2:end).^2);
The " ' " in Matlab is 'transpose' of a matrix. The
numpy package is the fundamental package for scientific computing in python.
numpy.transpose could be used to carry the same task out.
import numpy as np matrix = np.arange(6).reshape((2,3))
This going to create a matrix with two rows and three columns as follows :
>>> array([[0, 1, 2],[3, 4, 5]])
Then the transpose is given as:
np.transpose (matrix) >>> array([[0, 3],[1, 4],[2, 5]])
I hope it helps