user3104459 user3104459 - 5 months ago 8
Java Question

Why does a method require return statement in catch even though catch is re-throwing exception

I have written a method which is returning some value in try statement. Inside catch I am calling handleException which will have conversion logic of understanding the exception and rethrowing new exception. Here handleException is always throwing exception, still the getXYZ() gives compile time error expecting return statement. I am not handling the exception, I am just throwing new exception so why does the method wants return statement.

public String getXYZ(String input) {
try {
return getFromDAO(input);
} catch (Exception e) {
handleException(e);
}
}
private void handleException(Exception e) {
try {
throw e;
} catch(SomeException se) {
throw new MyRuntimeException("MyException message", se);
} catch(SomeOtherException soe) {
throw new MyRuntimeException("MyException message", soe);
}
}


The other version of this method compiles.

public String getXYZ(String input) {
try {
return getFromDAO(input);
} catch (Exception e) {
throw e;
}
}

Answer

You are not throwing anything in the catch block, you're calling your handle function, which ultimately will result in a new exception being thrown, but the actual code in getXYZ is doing a function call in catch. What if you change handleException to later not throw an exception in some circumstances, what would getXYZ return then?

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