Ilya Nikiforov - 2 months ago 6

Ruby Question

Is there a method in ruby to turn fixnum like 74239 into an array like [7,4,2,3,9]?

Answer

You don't need to take a round trip through string-land for this sort of thing:

```
def digits(n)
Math.log10(n).floor.downto(0).map { |i| (n / 10**i) % 10 }
end
ary = digits(74239)
# [7, 4, 2, 3, 9]
```

This does assume that `n`

is positive of course, slipping an `n = n.abs`

into the mix can take care of that if needed. If you need to cover non-positive values, then:

```
def digits(n)
return [0] if(n == 0)
if(n < 0)
neg = true
n = n.abs
end
a = Math.log10(n).floor.downto(0).map { |i| (n / 10**i) % 10 }
a[0] *= -1 if(neg)
a
end
```

Source (Stackoverflow)

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