Python Sum individual integers

Question

I want to make a python app that sums the numbers of a birthdate.

day = raw_input("What day were you born?")

month = raw_input("What month were you born?")

year = raw_input("What year were you born?")

day = int(day)

month = int(month)

year = int(year)

Let's say that someone was born on 12/10/1928; how could I make this app to sum it like this: 1+2+1+0+1+9+2+8?
This is done on Python 2.7

PS: I forgot to mention that my final result must be a one digit number so for example in the sum above the result is 24 but that number must sum itself so 2 + 4 = 6, being 6 the final answer.

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Answer 1

Instead of casting them as integers, add them as strings and then map each character as an integer and find the sum:

day = raw_input("What day were you born?")
month = raw_input("What month were you born?")
year = raw_input("What year were you born?")
print sum(map(int, day+month+year))

If you want to keep adding the digits until you arrive at a one-digit number, use a loop:

day = raw_input("What day were you born?")
month = raw_input("What month were you born?")
year = raw_input("What year were you born?")
num = day+month+year
while len(num) > 1:
    num = str(sum(map(int, num)))
print num

Python Sum individual integers

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