the_t_test_1 the_t_test_1 - 7 months ago 92
HTML Question

Get meta tag content property with BeautifulSoup and Python

I am trying to use python and beautiful soup to extract the content part of the tags below:

<meta property="og:title" content="Super Fun Event 1" />
<meta property="og:url" content="http://superfunevents.com/events/super-fun-event-1/" />


I'm getting BeautifulSoup to load the page just fine and find other stuff (this also grabs the article id from the id tag hidden in the source), but I don't know the correct way to search the html and find these bits, I've tried variations of find and findAll to no avail. The code iterates over a list of urls at present...

#!/usr/bin/env python
# -*- coding: utf-8 -*-

#importing the libraries
from urllib import urlopen
from bs4 import BeautifulSoup

def get_data(page_no):
webpage = urlopen('http://superfunevents.com/?p=' + str(i)).read()
soup = BeautifulSoup(webpage, "lxml")
for tag in soup.find_all("article") :
id = tag.get('id')
print id
# the hard part that doesn't work - I know this example is well off the mark!
title = soup.find("og:title", "content")
print (title.get_text())
url = soup.find("og:url", "content")
print (url.get_text())
# end of problem

for i in range (1,100):
get_data(i)


If anyone can help me sort the bit to find the og:title and og:content that'd be fantastic!

Answer

Provide the meta tag name as the first argument to find(). Then, use keyword arguments to check the specific attributes:

title = soup.find("meta",  property="og:title")
url = soup.find("meta",  property="og:url")

print(title["content"] if title else "No meta title given")
print(url["content"] if url else "No meta url given")

The if/else checks here would be optional if you know that the title and url meta properties would always be present.

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