Anton Anton - 3 months ago 20
Android Question

Make a link in the Android browser start up my app?

Is it possible to make a link such as:

<a href="anton://useful_info_for_anton_app">click me!</a>


cause my Anton app to start up?

I know that this works for the Android Market app with the market protocol, but can something similar be done with other apps?

Here is an example of a link that will start up the Android Market:

<a href="market://search?q=pname:com.nytimes.android">click me!</a>


Update:
The answer I accepted provided by eldarerathis works great, but I just want to mention that I had some trouble with the order of the subelements of the
<intent-filter>
tag. I suggest you simply make another
<intent-filter>
with the new subelements in that tag to avoid the problems I had. For instance my
AndroidManifest.xml
looks like this:

<activity android:name=".AntonWorld"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<data android:scheme="anton" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.BROWSABLE" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
</activity>

Answer

I think you'll want to look at the <intent-filter> element of your Mainfest file. Specifically, take a look at the documentation for the <data> sub-element.

Basically, what you'll need to do is define your own scheme. Something along the lines of:

<intent-filter>
    <data android:scheme="anton" />
    <action android:name="android.intent.action.VIEW" />
    <category android:name="android.intent.category.DEFAULT" />
    <category android:name="android.intent.category.BROWSABLE" /> <--Not positive if this one is needed
    ...
</intent-filter>

Then you should be able to launch your app with links that begin with the anton: URI scheme.

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