Darshan - 3 months ago 5

Scala Question

`val temp1 = tempTransform.map({ temp => ((temp.getShort(0), temp.getString(1)), (USAGE_TEMP.getDouble(2), USAGE_TEMP.getDouble(3)))})`

.reduceByKey((x, y) => ((x._1+y._1),(x._2+y._2)))

Here I have performed Sum operation But Is it possible to do

Like what i think,

`reduceByKey((x, y) => (math.count(x._1),(x._2+y._2)))`

But this is not working any suggestion please.

Answer

Well, counting is equivalent to summing `1`

s, so just map the first item in each value tuple into `1`

and sum both parts of the tuple like you did before:

```
val temp1 = tempTransform.map { temp =>
((temp.getShort(0), temp.getString(1)), (1, USAGE_TEMP.getDouble(3)))
}
.reduceByKey((x, y) => ((x._1+y._1),(x._2+y._2)))
```

Result would be an `RDD[((Short, String), (Int, Double))]`

where the first item in the value tuple (the `Int`

) is the number of original records matching that key.

That's actually the classic map-reduce example - word count.

Source (Stackoverflow)

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