Sojers - 6 months ago 36

R Question

If I have an array

`a = c(1,2,3,1,2,3,1,2,3,1,2,3)`

I would like to apply the "which" function to each scalar in 1:3

`l = list()`

for(i in 1:3){

l[[i]] = which(a == i)

}

how do I vectorize this operation with a apply, lapply, Map?

Answer

The main argument of `lapply`

should be the dimension of list elements you want to end up with. Which is the what you are looping over in your `for`

example, so:

```
a = c(1,2,3,1,2,3,1,2,3,1,2,3)
lapply(1:3, function(x) which(a == x))
```

Alternatively, if you don't want to code `a`

into the anonymous function you can use:

```
lapply(1:3, function(x, y) which(y == x), y = a)
```