LiL_Cj - 8 days ago 4x

Python Question

I'm trying to output a right triangle with numbers. Here is what I have so far:

`for i in range(1, 10):`

for j in range(i):

print(i, end='')

print()

My output is this

`1`

22

333

4444

55555

666666

7777777

88888888

999999999

My question is this. Can I make these numbers run in sequence using a nested for loop

example:

`1`

12

123

1234

12345

123456

1234567

12345678

123456789

I've tried about 6 other sets and mostly keep getting the same output or multiple errors. Can anyone help me out with this?

Answer

You might want to consider what happens next? This gives you a few ideas.

```
import itertools
for i in range(1, 21):
cycle = itertools.cycle([1,2,3,4,5,6,7,8,9,0])
for j in range(i):
print(next(cycle), end="")
print()
```

This cycles through the digits giving you output as follows:

```
1
12
123
1234
12345
123456
1234567
12345678
123456789
1234567890
12345678901
123456789012
1234567890123
12345678901234
123456789012345
1234567890123456
12345678901234567
123456789012345678
1234567890123456789
12345678901234567890
```

Or alternatively:

```
for i in range(1, 21):
for j in range(i):
print(((j % 10) + 1) % 10, end="")
print()
```

Source (Stackoverflow)

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