Aaron - 1 year ago 50

Javascript Question

My function to find the lowest element in alphabetical order in a sorted rotated array seems to work when the element is in the middle of the array and when the element is at the beginning of the array. What I cannot figure out is how to get the code to work when the element is at the end of the array. The smallest element in "Anna". Here is my code

`function sorted_array(arr){`

var first = 0;

var middle = arr.length/2;

var last = arr.length-1;

while(true){

if(arr[middle-1] > arr[middle] && arr[middle+1] > arr[middle] || middle === first

|| middle == last){

return arr[middle];

}

if(arr[middle] > arr[last] ){

first = middle;

middle = Math.floor((middle + last)/2);

} else{

last = middle;

middle = Math.floor((first + middle)/2);

}

}

}

var arr = [ "Celeste",

"Elon", "Giggli", "Jay", "Mavis", "Phoebe", "Thunder", "Anna"];

console.log(sorted_array(arr));

Answer Source

When you move the `middle`

pointer, you need to round it up, e.g. `(middle + left + 1)/2`

in the part where you search the later part of the array. Otherwise you will never reach the last item.

In your case you get `middle = 6, last = 7`

, `(6+7)/2 = 6,5 ==> 6`

.

Also in your stopping condition, you should check if `middle === last || middle === first`

before the value check to prevent invalid index errors.