Flogo Flogo - 2 months ago 6x
C Question

What‘s the difference between srand(1) and srand(0)

I just found out the hard way that

resets the PRNG of C(++) to the state before any call to
(as defined in the reference).
However, the seed 0 seems to do the same, or the state before any call to
seems to use the seed 0.
What’s the difference between those two calls or what is the reason they do the same thing?

For example this code (execute on Ideone)

#include <stdio.h>
#include <stdlib.h>

int main() {
for (int seed = 0; seed < 4; seed++ ) {
printf( "Seed %d:", seed);
srand( seed );
for(int i = 0; i < 5; i++ )
printf( " %10d", rand() );
printf( "\n");
return 0;


Seed 0: 1804289383 846930886 1681692777 1714636915 1957747793
Seed 1: 1804289383 846930886 1681692777 1714636915 1957747793
Seed 2: 1505335290 1738766719 190686788 260874575 747983061
Seed 3: 1205554746 483147985 844158168 953350440 612121425


It is probably an implementation detail. The standard mandates that the random seed 1 is special, and the internal register of your specific random generator algorithm is probably zero-initialized, thus causing the same random sequence for seed(0) and seed(1). I'd even wager that the first line of your srand() implementation looks like:

if ( seed == 1 ) seed = 0;

to force standard-conformant behaviour.

Generally, the random number generators for rand() and srand() are not required to give different sequences for different seeds, but the same sequence for the same seed. So, don't rely on different seeds generating different random sequences, and you should be fine. If not, welcome to implementation-specific fun.