Evert van de Lustgraaf Evert van de Lustgraaf - 5 months ago 9
SQL Question

Integrity constraint violation: 1062 Duplicate entry '1' for key 'PRIMARY'

I have a databse problem where i get Integrity constraint violation: 1062.
I tried some things on my own but it didtn work so now i am asking you guys to see if you people can help me out.

elseif($action == 'add') {
if($_POST['create'] == true) {
$title = $_POST['txtTitle'];
$txtParentCategorie = $_POST['txtParentCategorie'];
$txtContent = $_POST['txtContent'];

if($txtParentCategorie == "niks") {
$txtParentCategorie = NULL;
$chkParent = 1;
$order_count = countQuery("SELECT categorieID FROM prod_categorie WHERE parentID=?",array(1));
$order = $order_count + 1;
} else {
$chkParent = null;
$order_count = countQuery("SELECT categorieID FROM prod_categorie WHERE parentID is not NULL");
$order = $order_count + 1;
}

Query("INSERT INTO prod_categorie (categorieID, parentID) VALUES (?, ?)", array($chkParent, $txtParentCategorie));
$inserted_id = getLastInsertId();
Query("INSERT INTO tekst (tabel, kolom, item_id, tekst, taalID) VALUES(?, ?, ?, ?, ?)", array('prod_categorie', 'categoriename', $inserted_id, $title, $lang));
Query("INSERT INTO tekst (tabel, kolom, item_id, tekst, taalID) VALUES(?, ?, ?, ?, ?)", array('prod_categorie', 'content', $inserted_id, $txtContent, $lang));
$languages = selectQuery("SELECT taalID FROM taal WHERE taalID!=?",array($lang));
}


when i run this the first INSERT INTO doesnt fill in any data and giving this error:
Integrity constraint violation: 1062 Duplicate entry '1' for key 'PRIMARY'
there already is a primary 1 key in there. but it is on auto increment.
in the tekst tabel the item_id gets an 0 input.

Javascript:

$('.btnAddCategorie').click(function(){
if(busy != 1){
busy = 1;
var error = 0;
var gallery = $('select[name="gallery_dropdown"]').val();
if($('input[name="txtTitle"]').val() == ''){
error = 1;
alert('Het titel veld is nog leeg');
$('input[name="txtTitle"]').focus();
}
if(error != 1){
$('.content_load_icon').html('<img src="../../includes/images/layout/load_small.gif" />');
var content = $('#cke_ckeditor').children().children().children()[3].contentWindow.document.childNodes[1].childNodes[1].innerHTML;
$.ajax({
url: '../../action/ac_productbeheer.php?a=add',
type: 'POST',
data: {txtTitle: $('input[name="txtTitle"]').val(), txtForm: $('select[name="txtForm"]').val(), customGalTitle: $('.txtCustomGalleryTitle').val(), gallery_dropdown: gallery, txtParentCategorie: $('select[name="txtParentCategorie"]').val(), txtContent: content, txtMeta: $('.txtMetaDesc').val(), create: true},
success: function(data, textStatus, xhr) {
$('.content_load_icon').html('');
$('.txtContentConsole').html('Product succesvol opgeslagen!').show().delay(2000).fadeOut(200);
busy = 0;
saved = 1;
window.location = '../../modules/productbeheer/index.php';
},
error: function(xhr, textStatus, errorThrown) {
$('.content_load_icon').html('');
$('.txtContentConsole').html('Fout bij opslaan! Probeer het later nog een keer.').show().delay(2000).fadeOut(200);
busy = 0;
}
});
} else {
error = 0;
busy = 0;
}
}
});


html:

<a class="btnAddCategorie"><img name="btnOpslaan" src="/'.CMS_ROOT.'/includes/images/layout/opslaan.png" /></a><span class="content_load_icon"></span><span class="txtContentConsole"></span>


Hope someone can help me on here.
already alot of thanks in advance. :)

Answer

When inserting into a table with an auto increment field, the auto increment field itself should not be specified at all.

Query("INSERT INTO prod_categorie (categorieID, parentID) VALUES (?, ?)", array($chkParent, $txtParentCategorie));
                                   ^^^^^^^^^^^                    ^             ^^^^^^^^^^

Should be just

Query("INSERT INTO prod_categorie (parentID) VALUES (?)", array($txtParentCategorie));

Just added as answer from comment discussion to allow accept and finishing the question.