Toni - 1 year ago 88

R Question

I am trying to determine the first decimal place value different from zero. For example, in

`0.0000082109314`

`8`

I thought about a loop, but it's not working. So I'd rather ask in

`d = runif(100, min = 1e-10, max = 1e-5) # Toy data with 100 elements in a vector`

position = rep(0, 100) # Starting an empty vector to place results

for(j in 1:100){ # Looping through d

for(i in 1:10){ # Exponents from 1 to 10

if(d[j]]) * 10^i >= 1) # First power of 10 turning the value > or = 1

position[j] = i # Assign i to the position

stop the looping through i and move on to the next j

}

}

So I need the loop to stop replacing the

`i`

`i`

I know about

`break`

`next`

The issue is to at some point within the loop (when the condition is met) to ask R to 1. Save the index, and 2. Move on to the next

`j`

`position = rep(0, 100)`

for(j in 1:100){

for(i in 1:10){

if(d[j]]) * 10^i >= 0) position[j] = i AND next

else

CONTINUE with i

}

}

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

`break`

will kick you out of your current loop. It won't go all the way to the top level so if you use it inside of the loop indexed by i it will basically just kick you to the next value for j and restart i at 1.

Just as a note if you're going to have multiple conditions inside of your `if`

statement make sure to wrap all of them in curly braces.

```
for(j in 1:3){
for(i in 1L:6L){
# The result of this if statement is that we skip this iteration
# when i==2.
if(i == 2){
next
}
# The result of this if statement is that we kick out of the
# for loop indexed by i. The result being that we reach the end
# of the code block for the for loop indexed by j so if we aren't
# finished iterating over all of the values for j we go to the next
# value for j and start the for loop with i all over again.
if(i == 5){
break
}
# Just print out what i and j are equal to. We do this after the
# if statements so any iteration that isn't stopped by the if
# statements will end up printing a result.
print(sprintf("i: %i j: %i", i, j))
}
}
```

gives the output

```
[1] "i: 1 j: 1"
[1] "i: 3 j: 1"
[1] "i: 4 j: 1"
[1] "i: 1 j: 2"
[1] "i: 3 j: 2"
[1] "i: 4 j: 2"
[1] "i: 1 j: 3"
[1] "i: 3 j: 3"
[1] "i: 4 j: 3"
```

so by using next I skip every iteration where i==2 and by using break I stop anything for i>=5 and move on to the next value for j

If you were having troubles getting break to work with your code you'd need to post what you actually tried. There were issues other than 'break' in your code (you use d[j]] notice the mismatched square braces and I think you messed up your parenthesis on your if statement). This is what I think you wanted:

```
d = runif(100, min = 1e-10, max = 1e-5) # Toy data with 100 elements in a vector
position = rep(0, 100) # Starting an empty vector to place results
for(j in 1:100){ # Looping through d
for(i in 1:10){ # Exponents from 1 to 10
if((d[j] * 10^i) >= 1){ # First power of 10 turning the value > or = 1
position[j] = i # Assign i to the position
break
}
}
}
```

Recommended from our users: **Dynamic Network Monitoring from WhatsUp Gold from IPSwitch**. ** Free Download**