Ackman Ackman - 1 month ago 20
Java Question

Check internet connection OKHTTP

I am using the following code to make an api call and direct user to a page based on the response received. How do I check for internet connection?

I am using an OK HTTP client and my code looks like:

button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String url = "https://xxxxxxxx/" + orderLineId;
JSONObject jSon = new JSONObject();
try {
jSon.put("prescription_xxxxx", prescriptionIntervalId);
jSon.put("prescription_xxxxxxx", false);
} catch (JSONException e) {
e.printStackTrace();
}
String data = jSon.toString();
RequestBody body = RequestBody.create(JSON, data);
Request request = new Request.Builder()
.url(url)
.addHeader("Content-Type", "application/json")
.addHeader("Authorization", token)
.addHeader("Accept", "application/json")
.put(body)
.build();

client.newCall(request).enqueue(new Callback() {@Override
public void onFailure(Request request, IOException e) {

AlertDialog.Builder dialog = new AlertDialog.Builder(AutoRefillActivity.this);
dialog.setMessage("Something went wrong. Check connection.")
.setCancelable(false)
.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
onBackPressed();
}
});
AlertDialog alert = dialog.create();
alert.show();
}

@Override
public void onResponse(Response response) throws IOException {

if(response.code()==401){

AlertDialog.Builder dialog = new AlertDialog.Builder(AutoRefillActivity.this);
dialog.setMessage("Device was idle for too long please login again.")
.setCancelable(false)
.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
onBackPressed();
}
});
AlertDialog alert = dialog.create();
alert.show();

}
else {

Intent paymentSummary = new Intent(AutoRefillActivity.this,PPPaymentSummaryActivityNew.class);
paymentSummary.putExtra(PPPaymentSummaryActivityNew.EXTRA_ORDER,String.valueOf(orderLineId));
paymentSummary.putExtra("order_line_id",orderLineId);
paymentSummary.putExtra(PPPaymentSummaryActivityNew.EXTRA_CATEGORY_CODE,categoryCode);
paymentSummary.putExtra("prescriptionIntervalId",prescriptionIntervalId);
paymentSummary.putExtra("available",available);
paymentSummary.putExtra("token",token);
Bundle newBundle = new Bundle();
newBundle.putParcelable(PPPaymentSummaryActivityNew.EXTRA_PRODUCT,product);
paymentSummary.putExtras(newBundle);
startActivity(paymentSummary);

}
}


Though I have put an alert box in onFailure of the async request. It DOES NOT work. I can still turn off internet and my app crashes. Any solution to this?

Answer

the following method will determine whether internet is available

/**
     *
     * @param context
     * @return true if connected to internet
     */
    public static boolean isNetworkAvailable(Context context) {
        try {
            ConnectivityManager cm = (ConnectivityManager)
                    context.getSystemService(context.CONNECTIVITY_SERVICE);
            NetworkInfo networkInfo = cm.getActiveNetworkInfo();
            // if no network is available networkInfo will be null
            // otherwise check if we are connected
            if (networkInfo != null && networkInfo.isConnected()) {
                return true;
            }
            return false;
        } catch (Exception ex) {
            return false;
        }
    }

Then do your web service stuff like that

if(isNetworkAvailable(context)){
   //do something
}
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