TheCurlyManLives - 1 year ago 72

R Question

I am trying to build a Polya Urn model. Two colours went fine, with three however I ran into some trouble.

`ndraws<-1000; nexps<-2000; Distribution.yellow<-matrix(0,ndraws,1); for (k in 1:nexps){`

red<- 1;

yellow<- 1;

blue<-1 ;

for (n in 1:ndraws){

drawn<-sample(0:2,size=1,prob=c(red,yellow,blue)/(red+yellow +blue))

red<-?? ;

blue<-?? ;

yellow<-?? ;

}

Distribution.yellow[k]<-yellow/(red+yellow+blue) }

My problem lies in translating this line of code:

`drawn<-sample(0:2,size=1,prob=c(red,yellow,blue)/(red+yellow +blue))`

Into the respective extra balls added to the urn. (hence the question marks).

With two colours I did it as follows:

`drawn<-sample(0:1,size=1,prob=c(red,blue)/(red+blue))`

red<-red+(1-drawn);

blue<-blue+(drawn);

But this obviously does not work when there's more than two colours. How should I approach with three or more colours?

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Answer Source

According to Wikipedia, the rules for a PĆ³lya urn process are:

one ball is drawn randomly from the urn and its color observed; it is then returned in the urn, and an additional ball of the same color is added to the urn, and the selection process is repeated.

In other words, drawing a ball increments the number of balls of that colo(u)r by one.

So we can set up an `if`

statement that adds one red ball if `drawn==0`

, one yellow ball if `drawn==1`

, and one blue ball otherwise ...

```
ndraws <- 1000
nexps <- 500
set.seed(101)
yellow_final <- numeric(nexps)
for (k in 1:nexps) {
red <- 1; yellow <- 1; blue<-1
for (n in 1:ndraws) {
drawn <- sample(0:2,size=1,prob=c(red,yellow,blue)/(red+yellow+blue))
if (drawn==0) {
red <- red+1
} else if (drawn==1) {
yellow <- yellow+1
} else blue <- blue+1
}
yellow_final[k]<-yellow/(red+yellow+blue)
}
```

A picture:

```
par(las=1,bty="l")
hist(yellow_final,col="gray",freq=FALSE,
xlab="Prop. yellow after 1000 draws")
```