ssjadon ssjadon - 9 months ago 92
Python Question

python sort list of lists with tie-breaker

What is the most pythonic way to sort a list of lists with a tie-breaker?

I can sort by sub-list length (longest to shortest):

>>> l = [['c'], ['a', 'b'], ['b', 'c'], ['a', 'b', 'c']]

>>> list(reversed(sorted(l, key=len)))
[['a', 'b', 'c'], ['b', 'c'], ['a', 'b'], ['c']]

But I want to preserve order when the lengths are equal, so the output I want is:

[['a', 'b', 'c'], ['a', 'b'], ['b', 'c'], ['c']]


Timsort (Python's built-in sorting algorithm) is stable, meaning it keeps the original order of elements with equal keys. However, you reversed the original order by using the reversed function.

If you want to reverse the resulting list and preserve the original order of elements comparing equal, use reverse=True:

In [3]: sorted(l, key=len, reverse=True)
Out[3]: [['a', 'b', 'c'], ['a', 'b'], ['b', 'c'], ['c']]