In Python what is equivalent to Ruby's Array.each method? Does Python have a nice and short closure/lambda syntax for it?
[1,2,3].each do |x|
Does Python have a nice and short closure/lambda syntax for it?
Yes, but you don't want it in this case.
The closest equivalent to that Ruby code is:
new_values = map(print, [1, 2, 3])
That looks pretty nice when you already have a function lying around, like
map, you need to create a function out of it with a
def or a
lambda, like this:
new_values = map(lambda x: print(x), [1, 2, 3])
That's the ugliness you apparently want to avoid. And Python has a nice way to avoid it: comprehensions:
new_values = [print(x) for x in values]
However, in this case, you're just trying to execute some statement for each value, not accumulate the new values for each value. So, while this will work (you'll get back a list of
None values), it's definitely not idiomatic.
In this case, the right thing to do is to write it explicitly—no closures, no functions, no comprehensions, just a loop:
for x in values: print x