Flix Flix - 1 month ago 34
Java Question

How to display JSONObject into TextView on android

I've set up a php script to create json here, but when i try to display the JSONobject i got some error like this on my Android Monitor..


Value (html)(body)(script of type java.lang.String cannot be converted to JSONObject


can someone tell me how to fix it? below my code to try


my MainActivity.java




package flix.yudi.okhttp1;
import android.app.ProgressDialog;
import android.os.AsyncTask;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.util.Log;
import android.widget.ListAdapter;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.Toast;

import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import java.util.ArrayList;
import java.util.HashMap;

public class MainActivity extends AppCompatActivity {

private String TAG = MainActivity.class.getSimpleName();

private ProgressDialog pDialog;
private ListView lv;

// URL to get contacts JSON
private static String url = "http://zxccvvv.cuccfree.com/send_data.php";

ArrayList<HashMap<String, String>> contactList;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

contactList = new ArrayList<>();

lv = (ListView) findViewById(R.id.list);

new GetContacts().execute();
}

/**
* Async task class to get json by making HTTP call
*/
private class GetContacts extends AsyncTask<Void, Void, Void> {

@Override
protected void onPreExecute() {
super.onPreExecute();
// Showing progress dialog
pDialog = new ProgressDialog(MainActivity.this);
pDialog.setMessage("Please wait...");
pDialog.setCancelable(false);
pDialog.show();

}

@Override
protected Void doInBackground(Void... arg0) {
HttpHandler sh = new HttpHandler();

// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url);

Log.e(TAG, "Response from url: " + jsonStr);

if (jsonStr != null) {
try {
JSONObject jsonObj = new JSONObject(jsonStr);

// Getting JSON Array node
JSONArray contacts = jsonObj.getJSONArray("");

// looping through All Contacts
for (int i = 0; i < contacts.length(); i++) {
JSONObject c = contacts.getJSONObject(i);

String id = c.getString("id");
String ask = c.getString("ask");

// tmp hash map for single contact
HashMap<String, String> contact = new HashMap<>();

// adding each child node to HashMap key => value
contact.put("id", id);
contact.put("ask", ask);

// adding contact to contact list
contactList.add(contact);
}
} catch (final JSONException e) {
Log.e(TAG, "Json parsing error: " + e.getMessage());
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Json parsing error: " + e.getMessage(),
Toast.LENGTH_LONG)
.show();
}
});

}
} else {
Log.e(TAG, "Couldn't get json from server.");
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Couldn't get json from server. Check LogCat for possible errors!",
Toast.LENGTH_LONG)
.show();
}
});

}

return null;
}

@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
// Dismiss the progress dialog
if (pDialog.isShowing())
pDialog.dismiss();
/**
* Updating parsed JSON data into ListView
* */
ListAdapter adapter = new SimpleAdapter(
MainActivity.this, contactList,
R.layout.list_item, new String[]{"ask"}, new int[]{R.id.ask});

lv.setAdapter(adapter);
}

}
}



my HttpHandler.java




package flix.yudi.okhttp1;

import android.util.Log;

import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.ProtocolException;
import java.net.URL;

public class HttpHandler {

private static final String TAG = HttpHandler.class.getSimpleName();

public HttpHandler() {
}

public String makeServiceCall(String reqUrl) {
String response = null;
try {
URL url = new URL(reqUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
// read the response
InputStream in = new BufferedInputStream(conn.getInputStream());
response = convertStreamToString(in);
} catch (MalformedURLException e) {
Log.e(TAG, "MalformedURLException: " + e.getMessage());
} catch (ProtocolException e) {
Log.e(TAG, "ProtocolException: " + e.getMessage());
} catch (IOException e) {
Log.e(TAG, "IOException: " + e.getMessage());
} catch (Exception e) {
Log.e(TAG, "Exception: " + e.getMessage());
}
return response;
}

private String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();

String line;
try {
while ((line = reader.readLine()) != null) {
sb.append(line).append('\n');
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
}


I got the reference code from here

someone can help me how to fix the error?


Edited code




if (jsonStr != null) {
try {
JSONArray jsonObj = new JSONArray(jsonStr);

// Getting JSON Array node
JSONArray pertanyaan = jsonObj.getJSONArray("pertanyaan");

// looping through All Contacts
for (int i = 0; i < pertanyaan.length(); i++) {
JSONArray c = pertanyaan.getJSONArray(i);

String id = c.getString("id");
String ask = c.getString("ask");

Answer

If you have access to server then you could make it return a string in the following format:

{"contacts":[{"id":"1","ask":"pertanyaan ke 1"},{"id":"2","ask":"pertanyaan ke 2"},{"id":"3","ask":"pertanyaan ke 3"},{"id":"4","ask":"pertanyaan ke 4"},{"id":"5","ask":"pertanyaan ke 5"}]}

if you want to read it as JSONObject with JSONObject jsonObj = new JSONObject(jsonStr);

and then use JSONArray contacts = jsonObj.getJSONArray("contacts"); to parse it


After your edits:

Change this JSONArray c = pertanyaan.getJSONArray(i); to this JSONObject c = pertanyaan.getJsonObject(i)

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