Brian - 1 year ago 96
Python Question

# Numeric Sort in Python

I know that this sounds trivial but I did not realize that the

`sort()`
function of Python was weird. I have a list of "numbers" that are actually in string form, so I first convert them to ints, then attempt a sort.

``````list1=["1","10","3","22","23","4","2","200"]
for item in list1:
item=int(item)

list1.sort()
print list1
``````

Gives me:

``````['1', '10', '2', '200', '22', '23', '3', '4']
``````

What I want is

``````['1','2','3','4','10','22','23','200']
``````

I've looked around for some of the algorithms associated with sorting numeric sets, but the ones I found all involve sorting alphanumeric sets.

I know this is probably a no brainer problem but google and my textbook don't offer anything more or less useful than the
`.sort()`
function.

You haven't actually converted your strings to ints. Or rather, you did, but then you didn't do anything with the results. What you want is:

``````list1 = ["1","10","3","22","23","4","2","200"]
list1 = [int(x) for x in list1]
list1.sort()
``````

However, python makes it even easier for you: sort takes a named parameter, key, which is a function that is called on each element before it is compared (but without modifying the list)

``````list1 = ["1","10","3","22","23","4","2","200"]
# call int(x) on each element before comparing it
list1.sort(key=int)
``````
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