infernouk infernouk - 1 year ago 85
Swift Question

Filtering Array and displaying in Table View?

I want to search an dictionary of exercises for the name key and then show the filtered result in the table view. I am using this function

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
let filtered = exercises.filter { $0["name"] == searchText }

if(filtered.count == 0){
searchActive = false;
} else {
searchActive = true;


var exercises = [Exercise]()
var filtered: [NSMutableArray] = []
var searchActive: Bool = false

In the search function I get the error

Type'Exercise' has no subscript members

and then i have the issue that the result is an NSMutableArray and so I cant set the result names as cell text to display

Cannot convert value of type 'NSMutableArray' to type 'String' in coercion

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "Cell", for: indexPath)
if (searchActive){
cell.textLabel?.text = filtered[indexPath.row] as String
} else {
let exercise = exercises[indexPath.row]

cell.textLabel!.text =
return cell

Here is my Exercise dictionary for reference:

final public class Exercise {
var id: Int
var descrip: String
var name: String
var muscles: [Int]
var equipment: [Int]

public init?(dictionary: [String: Any]) {

let id = dictionary["id"] as? Int,
let descrip = dictionary["description"] as? String,
let name = dictionary["name"] as? String,
let muscles = dictionary["muscles"] as? [Int],
let equipment = dictionary["equipment"] as? [Int]

else { return nil } = id
self.descrip = descrip = name
self.muscles = muscles = equipment


I can fix the second error by making var filtered: [String] = [] so it can be used as a cell title, but that doesnt resolve the first error and im not sure is the right way to go about it?

Answer Source

Your filtered also type of [Exercise] and you need to filter it like.

var filtered = [Exercise]() 

self.filtered = exercises.filter { $ == searchText }

Here $0 is type of Exercise object, so you need to access its property name using $

Edit: If you want filtered as type of [String] with only name then you can need to use both map and filter like this.

self.filtered = exercises.filter { $ == searchText }.map { $ }


self.filtered = { $ }.filter { $0 == searchText }

OR directly using filterMap as @dfri suggested.

self.filtered = exercises.flatMap{ $ == searchText ? $ : nil }
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