Chris - 10 days ago 5x

Python Question

I have a list of numbers and I would like to remove the LAST odd number from it. This code works well only when the last odd number is not repeated throughout the list before:

`numbers = [1, 7, 2, 34, 8, 7, 2, 5, 14, 22, 93, 48, 76, 15, 7]`

odd_numbers = []

def remove_last_odd(numbers):

for n in numbers:

if n % 2 != 0:

odd_numbers.append(n)

numbers.remove(odd_numbers[-1])

return numbers

So instead of removing the last 7, I end up removing the first occurrence of 7 in my "numbers" list.

Can anyone help?

Answer

not the most efficient way but will work:

```
def remove_last_odd(numbers):
rnumbers = numbers[::-1]
for n in rnumbers:
if n % 2 != 0:
rnumbers.remove(n)
break
return rnumbers[::-1]
```

basically do this: reverse list, remove first odd number, reverse again and return.

Source (Stackoverflow)

Comments