MD XF - 8 months ago 38

C Question

So I've got a program that runs through every possible alphanumerical combination between 0000000000 and ZZZZZZZZZZ. Currently I'm using this code:

`for (digit[0] = 0; digit[0] < 36; digit[0]++)`

for (digit[1] = 0; digit[1] < 36; digit[1]++)

for (digit[2] = 0; digit[2] < 36; digit[2]++)

// etc...

...and eventually there are 10 nested for loops and my entire editor screen is filled. So how would I condense this into one or two for loops? I can't find out how I would put them together testing and incrementing

`digit[i]`

Answer

Use an odometer algorithm. Increment the last digit. When it reaches the highest value, wrap it back to `0`

and recurse on the remaining digits, until you run out of digits.

```
int increment_digit(int array[], unsigned int index, limit) {
if (index == -1) { // We've wrapped around the entire set
return 0;
}
array[index]++;
if (array[index] == limit) {
array[index] = 0;
return increment_digit(array, index-1, limit);
} else {
return 1;
}
int main(int argc, char **argv) {
int digits[SIZE] = {0};
while (1) {
// do stuff ...
if (!increment_digit(digits, SIZE-1, 36))
break;
}
}
return 0;
}
```

Source (Stackoverflow)