ekjyot ekjyot - 4 months ago 11
Android Question

android.database.sqlite.SQLiteConstraintException: error code 19: constraint failedexception

I created a table named resources but when I insert values in it, this exception is thrown:

android.database.sqlite.SQLiteConstraintException:
error code 19: constraint failedexception


Here is my create table statement:

public static final String DATABASE_CREATE =
"CREATE TABLE " + table_resources + "(ID INTEGER PRIMARY KEY,
KEY_TYPE text, KEY_ENCODING text, KEY_WIDTH text, KEY_HEIGHT text,
KEY_DATA text, KeyIId text)";


The following is my insert code:

JSONObject show = data.getJSONObject(i);
if (show.get("type").equals("resource_updates")) {
JSONArray resources = show.getJSONArray("resources");
try {
System.out.println("length of resources is is " + resources.length());
for (int resourceIndex = 0; resourceIndex < resources.length(); resourceIndex++) {
type = resources.getJSONObject(resourceIndex).getString("type").toString();
encoding = resources.getJSONObject(resourceIndex).getString("encoding").toString();
data1 = resources.getJSONObject(resourceIndex).getString("data").toString();
id = resources.getJSONObject(resourceIndex).getString("id").toString();
try {
width = resources.getJSONObject(resourceIndex).getString("width").toString();
} catch (Exception e) {
System.out.println(e);
width = "null";
}
try {
height = resources.getJSONObject(resourceIndex).getString("height").toString();
} catch (Exception e) {
e.printStackTrace();
height = "null";
}
db.insert(type,encoding,width,height, data1,iid);
}
} catch (Exception e) {
e.printStackTrace();
System.out.println(e + "exception");
System.out.println("exception in the resources");
}
}


Can anyone tell me where could be the problem?

Answer

Constraint failed usually indicates that you did something like pass a null value into a column that you declare as not null when you create your table.