sling sling - 4 months ago 15
Java Question

Java: charAt convert to int?

I would like to key in my

nirc
number e.g.
S1234567I
and then put
1234567
individualy as a integer as
indiv1
as
charAt(1)
,
indiv2
as
charAt(2)
,
indiv
as
charAt(3)
, etc. However, when I use the code below, I can't seem to get even the first number out? Any idea?

Scanner console = new Scanner(System.in);
System.out.println("Enter your NRIC number: ");

String nric = console.nextLine();

int indiv1 = nric.charAt(1);
System.out.println(indiv1);

Answer

You'll be getting 49, 50, 51 etc out - those are the Unicode code points for the characters '1', '2', '3' etc.

If you know that they'll be Western digits, you can just subtract '0':

int indiv1 = nric.charAt(1) - '0';

However, you should only do this after you've already validated elsewhere that the string is of the correct format - otherwise you'll end up with spurious data - for example, 'A' would end up returning 17 instead of causing an error.

Of course, one option is to take the values and then check that the results are in the range 0-9. An alternative is to use:

int indiv1 = Character.digit(nric.charAt(1), 10);

This will return -1 if the character isn't an appropriate digit.

I'm not sure if this latter approach will cover non-Western digits - the first certainly won't - but it sounds like that won't be a problem in your case.