SoldierCorp SoldierCorp - 1 year ago 47
jQuery Question

How create table or append from JSON format?

After process a tiny search engine with ajax-jQuery, and functions in PHP, I've a Array JSON and I want process this for append rows in table exists but I get confused.

The JSON format from query mysql is OK, but I don't know how process data to generate table or append in my exists table.

I think that is applied each for taking each element of JSON but I can not think as.

Note: My JSON Code was generate to this this way

$jsonSearchResults = array();
while ($row = mysql_fetch_assoc($result)) {
$jsonSearchResults[] = array(
'clavemat' => $row['cve_mat'],
'tipomat' => $row['tipo_mat'],
'titulomat' => $row['titulo_mat'],
'autormat' => $row['autor_mat'],
'editmat' => $row['edit_mat'],
'success' => 'success'
echo json_encode ($jsonSearchResults);

Table HTML

<table class="busqueda">
<th scope="col">Clave</th>
<th scope="col">Tipo</th>
<th scope="col">Título</th>
<th scope="col">Autor</th>
<th scope="col">Editorial</th>


"autormat":"Elias Flores",
"editmat":"McGraw Hill",
"titulomat":"Curso java",
"editmat":"McGraw Hill",
"autormat":"Muy Interesante",
"editmat":"Muy interesante",
"titulomat":"Platanito Show",


type: "POST",
url: action,
data: dataSearch,
success: function (response) {

if (response[0].success == "success") {
alert("Si hay datos");
} else {
alert("No hay datos");

return false;

Answer Source

This should work

$.each(response, function (index, record) {
    var row = $("<tr />");
    $("<td />").text(record.clavemat).appendTo(row);
    $("<td />").text(record.tipomat).appendTo(row);
    $("<td />").text(record.titulomat).appendTo(row);
    $("<td />").text(record.autormat).appendTo(row);
    $("<td />").text(record.editmat).appendTo(row);


The above code appends rows to an existing table with class "busqueda".

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