Hal Lawrence - 11 months ago 56

Python Question

Learning python, but having trouble telling function to find consecutive locations with same values. When I run the code, there's no errors but gives out the incorrect output. Suggestions on what to change?

`def same_values(xs):`

same = False

for i in (xs):

if xs == xs[1:]:

same = True

else:

return same

same_values('Misses') # This should return as true

Answer Source

So you are looking for a consecutive pair in the list and returning true if you find one.

```
def same_values(xs):
for i in range(len(xs)-1):
if xs[i] == xs[i+1]:
return True
return False
>>> same_values('misses')
True
>>> same_values('mises')
False
```

Would give you the correct answer.

However python has a powerful iterator algebra. The advantage of this is that it would work with iterators (iterators don't generally support `len()`

) as well as lists:

```
import itertools as it
def same_values(xs):
a, b = it.tee(xs)
next(b, None)
return any(x == y for x, y in zip(a, b))
```

This pattern is described in the `itertools`

recipes as `pairwise`

:

```
import itertools as it
def pairwise(iterable):
"s -> (s0,s1), (s1,s2), (s2, s3), ..."
a, b = it.tee(iterable)
next(b, None)
return zip(a, b)
def same_values(xs):
return any(x == y for x, y in pairwise(xs))
```

For example to check if any 2 consecutive lines in a file are the same (this wouldn't work with the `list`

version):

```
with open('somefile') as f:
print(same_values(f))
```