Mr_and_Mrs_D Mr_and_Mrs_D - 1 year ago 63
Python Question

How to programmatically count the number of files in an archive using python

In the program I maintain it is done as in:

# count the files in the archive
length = 0
command = ur'"%s" l -slt "%s"' % (u'path/to/7z.exe', srcFile)
ins, err = Popen(command, stdout=PIPE, stdin=PIPE,
ins = StringIO.StringIO(ins)
for line in ins: length += 1

  1. Is it really the only way ? I can't seem to find any other command but it seems a bit odd that I can't just ask for the number of files

  2. What about error checking ? Would it be enough to modify this to:

    proc = Popen(command, stdout=PIPE, stdin=PIPE,
    out = proc.stdout
    # ... count
    returncode = proc.wait()
    if returncode:
    raise Exception(u'Failed reading number of files from ' + srcFile)

    or should I actually parse the output of Popen ?

EDIT: interested in 7z, rar, zip archives (that are supported by 7z.exe) - but 7z and zip would be enough for starters

Answer Source

To count the number of archive members in a zip archive in Python:

#!/usr/bin/env python
import sys
from contextlib import closing
from zipfile import ZipFile

with closing(ZipFile(sys.argv[1])) as archive:
    count = len(archive.infolist())

It may use zlib, bz2, lzma modules if available, to decompress the archive.

To count the number of regular files in a tar archive:

#!/usr/bin/env python
import sys
import tarfile

with[1]) as archive:
    count = sum(1 for member in archive if member.isreg())

It may support gzip, bz2 and lzma compression depending on version of Python.

You could find a 3rd-party module that would provide a similar functionality for 7z archives.

To get the number of files in an archive using 7z utility:

import os
import subprocess

def count_files_7z(archive):
    s = subprocess.check_output(["7z", "l", archive], env=dict(os.environ, LC_ALL="C"))
    return int('(\d+)\s+files,\s+\d+\s+folders$', s).group(1))

Here's version that may use less memory if there are many files in the archive:

import os
import re
from subprocess import Popen, PIPE, CalledProcessError

def count_files_7z(archive):
    command = ["7z", "l", archive]
    p = Popen(command, stdout=PIPE, bufsize=1, env=dict(os.environ, LC_ALL="C"))
    with p.stdout:
        for line in p.stdout:
            if line.startswith(b'Error:'): # found error
                error = line + b"".join(p.stdout)
                raise CalledProcessError(p.wait(), command, error)
    returncode = p.wait()
    assert returncode == 0
    return int('(\d+)\s+files,\s+\d+\s+folders', line).group(1))


import sys

except CalledProcessError as e:
    getattr(sys.stderr, 'buffer', sys.stderr).write(e.output)

To count the number of lines in the output of a generic subprocess:

from functools import partial
from subprocess import Popen, PIPE, CalledProcessError

p = Popen(command, stdout=PIPE, bufsize=-1)
with p.stdout:
    read_chunk = partial(, 1 << 15)
    count = sum(chunk.count(b'\n') for chunk in iter(read_chunk, b''))
if p.wait() != 0:
    raise CalledProcessError(p.returncode, command)

It supports unlimited output.

Could you explain why buffsize=-1 (as opposed to buffsize=1 in your previous answer:

bufsize=-1 means use the default I/O buffer size instead of bufsize=0 (unbuffered) on Python 2. It is a performance boost on Python 2. It is default on the recent Python 3 versions. You might get a short read (lose data) if on some earlier Python 3 versions where bufsize is not changed to bufsize=-1.

This answer reads in chunks and therefore the stream is fully buffered for efficiency. The solution you've linked is line-oriented. bufsize=1 means "line buffered". There is minimal difference from bufsize=-1 otherwise.

and also what the read_chunk = partial(, 1 << 15) buys us ?

It is equivalent to read_chunk = lambda:<<15) but provides more introspection in general. It is used to implement wc -l in Python efficiently.

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