Ramy George - 6 months ago 39

Python Question

The question is

For a quadratic equation in the form of ax^{2}+ bx + c, the

discriminant, D is b^{2}-4ac.

Write a function that return the following output depending on the discriminant.

- D > 0: 2 real roots.

- D = 0: 1 real root.

- D < 0: 2 complex roots.

Examples

`>>> quadratic(1, 2, 3)`

'This equation has 2 complex roots.'

>>> quadratic(1, 3, 2)

'This equation has 2 real roots.'

>>> quadratic(1, 4, 4)

'This equation has 1 real root.'

Python gave a "Private test cases failed" error. Where is my error?

`def quadrtic(a,b,c):`

d=b**2-4*a*c

if d<0:

return "This equation has 2 complex roots."

elif d==1:

return "This equation has 2 real roots."

elif d==0 or d==1:

return "This equation has 1 real root."

Answer

Your `if`

blocks should be

```
def quadrtic(a,b,c):
d = b**2 - 4*a*c
if d < 0:
return "This equation has 2 complex roots."
elif d > 0:
return "This equation has 2 real roots."
else: # d == 0
return "This equation has 1 real root."
```

The discriminant is very unlikely to be exactly `== 1`

. For it to have two real roots, it just must be greater than 0, the discriminant can be any real number in this case (e.g. 4.2564)

Source (Stackoverflow)