myfirsttime1 - 11 months ago 84

Python Question

I am trying to generate a matrix

`A == [f(i,j) for i,j in range(0,n)]`

`(f(i,j) == f(j,i))`

`(f(i,i) == 0)`

`f(i,j)`

`i < j`

`f`

`g`

`f`

Would it be possible to solve avoiding the additional storage?

I am not sure if this additional handicap implies that a reference to the list comprehension from itself (which I read doesn't exist in Python) is necessary, hopefully I am missing some other trick.

Answer Source

Assuming you really need the full matrix, in spite of its being symmetric, you could do this.

Create the matrix **A** first. (I know, this means you're not generating it in a list comprehension.) Here I define a 'dummy' function **f** and assume a value of 3 for **n**.

```
>>> n=3
>>> subs=((i,j) for i in range(n) for j in range(3) if i<=j)
>>> for i,j in subs:
... i,j
...
(0, 0)
(0, 1)
(0, 2)
(1, 1)
(1, 2)
(2, 2)
>>> def f(i,j):
... return
...
>>> def g(i,j):
... if i==j:
... A[i,i] = 0
... else:
... val=f(i,j)
... A[i,j]=val
... A[j,i]=val
```

If I've understood you correctly, there's no need for extra storage. Call **g** in a list comprehension that exercises **subs**.