Rich Bradshaw Rich Bradshaw - 8 months ago 42
Sass (Sass) Question

Making a Sass mixin with optional arguments

I am writing a mixin like this:

@mixin box-shadow($top, $left, $blur, $color, $inset:"") {
-webkit-box-shadow: $top $left $blur $color $inset;
-moz-box-shadow: $top $left $blur $color $inset;
box-shadow: $top $left $blur $color $inset;

When called what I really want is that if no
value is passed, nothing is output, rather than it compiling to something like this:

-webkit-box-shadow: 2px 2px 5px #555555 "";
-moz-box-shadow: 2px 2px 5px #555555 "";
box-shadow: 2px 2px 5px #555555 "";

How do I rewrite the mixin so that if there is no value of
passed, nothing is output?


A DRY'r Way of Doing It

And, generally, a neat trick to remove the quotes.

@mixin box-shadow($top, $left, $blur, $color, $inset:"") {
  -webkit-box-shadow: $top $left $blur $color #{$inset};
  -moz-box-shadow:    $top $left $blur $color #{$inset};
  box-shadow:         $top $left $blur $color #{$inset};

SASS Version 3+, you can use unquote():

@mixin box-shadow($top, $left, $blur, $color, $inset:"") {
  -webkit-box-shadow: $top $left $blur $color unquote($inset);
  -moz-box-shadow:    $top $left $blur $color unquote($inset);
  box-shadow:         $top $left $blur $color unquote($inset);

Picked this up over here: pass a list to a mixin as a single argument with SASS