I was trying to open a file for reading.
Scanner input = new Scanner(filename);
InputStream in = openFileInput(filename);
Scanner input = new Scanner(in);
Files are stored on the device in a specific, application-dependent location, which is what I suppose
openFileInput adds at the beginning of the file name. The final result (location + file name) is constructed as follows:
Note also that the documentation states that the
openFileInput parameter cannot contain path separators.
To avoid hard-coding the location path, which could in principle even be different from device to device, you can obtain a
File object pointing to the storage directory by calling
getFilesDir, and use it to read whatever file you would like to. For example:
File filesDir = getFilesDir(); Scanner input = new Scanner(new File(filesDir, filename));
Note that constructing a
Scanner by passing a
String as a parameter would result in the scanner working on the content of the string, i.e. interpreting it as the actual content to scan instead of as the name of a file to open.